(2^x+3)*(3^2x)=15

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Solution for (2^x+3)*(3^2x)=15 equation: 



(2^x+3)(3^2x)=15

We move all terms to the left:

(2^x+3)(3^2x)-(15)=0

We move all terms containing x to the left, all other terms to the right

(2^x+3)3^2x=15

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